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Cryptic Math Problem 2 Answer
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Y has to be 0 and T has to be even since TWENTY is divisible by 20.
E and O are even, using the same reasoning.
N is also even to satisfy O + Y and E + N.
Then W, L and V must be odd and two odd integers are not used.
E + N is less than 10 to satisfy WO + TY and VE + EN.
O + Y and E + N yields four possibilities for values of O, Y, E and N.
TWO + NTY and LVE + TEN yields three possibilities . But only 876 + 480 and 532 + 824 yields a TWELVE which is divisible by 12.
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