Cryptic Math Problem 2 AnswerA conclusion is the place where you got tired of thinking.
spc Bd 1 Bd 3
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Cryptic Math Problem 2 Answer

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Cryptic Math Problem 2 Answer



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Y has to be 0 and T has to be even since TWENTY is divisible by 20.

E and O are even, using the same reasoning.

N is also even to satisfy O + Y and E + N.

Then W, L and V must be odd and two odd integers are not used.

E + N is less than 10 to satisfy WO + TY and VE + EN.

O + Y and E + N yields four possibilities for values of O, Y, E and N.

TWO + NTY and LVE + TEN yields three possibilities . But only 876 + 480 and 532 + 824 yields a TWELVE which is divisible by 12.

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