|Black holes are where God divided by zero.|
Cryptic Math Problem 22 Answer
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N must be zero.
The only possibilities for O and B are: (2, 6), (4, 6), (5, 3), (5, 7), (5, 9) and (8, 6).
Then the only possibilities for DO x B = SO are: (12 x 6 = 72), (14 x 6 = 84) or (15 x 3 = 45).
If you try LY x B = JOH with each of those possibilities, you'll see that the only solution is the one above.
From The Numerology of Dr. Matrix by Martin Gardner
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