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This is the answer to one of our math puzzles. We have several other puzzles for you to try to figure out. Please click to see all our math puzzles.

The player would have an expected loss of 7.87 cents per game.

There are 216 (6³) possible dice throw permutations. If the player always bets on the same number, let's say 1, then there are four possible distributions of 1 and "not 1." Their probabilities are like this, where x stands for "not 1."

 x x x 125/216 1 x x 75/216 1 1 x 15/216 1 1 1 1/216

E = ((0)125 + (1 + 1)75 + (1 + 2)15 + (1 + 3)1) / 216 - 1 = -17/216 = -\$0.0787.

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