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Math Puzzle AnswerHere is the solution to one of our math puzzles. There are several other puzzles to solve. Please click to see all of our math puzzles.
Carnival Game  AnswerThe player would have an expected loss of 7.87 cents per game. There are 216 (6³) possible dice throw permutations. If the player always bets on the same number, let's say 1, then there are four possible distributions of 1 and "not 1." Their probabilities are like this, where x stands for "not 1."
That leads to: E = ((0)125 + (1 + 1)75 + (1 + 2)15 + (1 + 3)1) / 216  1 = 17/216 = $0.0787.


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